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we never assert on conditions that depend on the result of a computation!! also the assertion that rank>0 amounts to matrix!=0 which we have to leave under the responsibility of the user.
603 lines
23 KiB
C++
603 lines
23 KiB
C++
// This file is part of Eigen, a lightweight C++ template library
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// for linear algebra.
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//
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// Copyright (C) 2006-2008 Benoit Jacob <jacob.benoit.1@gmail.com>
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//
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// Eigen is free software; you can redistribute it and/or
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// modify it under the terms of the GNU Lesser General Public
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// License as published by the Free Software Foundation; either
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// version 3 of the License, or (at your option) any later version.
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//
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// Alternatively, you can redistribute it and/or
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// modify it under the terms of the GNU General Public License as
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// published by the Free Software Foundation; either version 2 of
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// the License, or (at your option) any later version.
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//
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// Eigen is distributed in the hope that it will be useful, but WITHOUT ANY
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// WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS
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// FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License or the
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// GNU General Public License for more details.
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//
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// You should have received a copy of the GNU Lesser General Public
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// License and a copy of the GNU General Public License along with
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// Eigen. If not, see <http://www.gnu.org/licenses/>.
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#ifndef EIGEN_LU_H
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#define EIGEN_LU_H
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/** \ingroup LU_Module
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*
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* \class LU
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*
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* \brief LU decomposition of a matrix with complete pivoting, and related features
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*
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* \param MatrixType the type of the matrix of which we are computing the LU decomposition
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*
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* This class represents a LU decomposition of any matrix, with complete pivoting: the matrix A
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* is decomposed as A = PLUQ where L is unit-lower-triangular, U is upper-triangular, and P and Q
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* are permutation matrices. This is a rank-revealing LU decomposition. The eigenvalues (diagonal
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* coefficients) of U are sorted in such a way that any zeros are at the end, so that the rank
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* of A is the index of the first zero on the diagonal of U (with indices starting at 0) if any.
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*
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* This decomposition provides the generic approach to solving systems of linear equations, computing
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* the rank, invertibility, inverse, kernel, and determinant.
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*
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* This LU decomposition is very stable and well tested with large matrices. Even exact rank computation
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* works at sizes larger than 1000x1000. However there are use cases where the SVD decomposition is inherently
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* more stable when dealing with numerically damaged input. For example, computing the kernel is more stable with
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* SVD because the SVD can determine which singular values are negligible while LU has to work at the level of matrix
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* coefficients that are less meaningful in this respect.
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*
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* The data of the LU decomposition can be directly accessed through the methods matrixLU(),
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* permutationP(), permutationQ().
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*
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* As an exemple, here is how the original matrix can be retrieved:
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* \include class_LU.cpp
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* Output: \verbinclude class_LU.out
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*
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* \sa MatrixBase::lu(), MatrixBase::determinant(), MatrixBase::inverse(), MatrixBase::computeInverse()
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*/
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template<typename MatrixType> class LU
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{
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public:
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typedef typename MatrixType::Scalar Scalar;
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typedef typename NumTraits<typename MatrixType::Scalar>::Real RealScalar;
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typedef Matrix<int, 1, MatrixType::ColsAtCompileTime> IntRowVectorType;
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typedef Matrix<int, MatrixType::RowsAtCompileTime, 1> IntColVectorType;
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typedef Matrix<Scalar, 1, MatrixType::ColsAtCompileTime> RowVectorType;
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typedef Matrix<Scalar, MatrixType::RowsAtCompileTime, 1> ColVectorType;
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enum { MaxSmallDimAtCompileTime = EIGEN_ENUM_MIN(
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MatrixType::MaxColsAtCompileTime,
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MatrixType::MaxRowsAtCompileTime)
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};
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typedef Matrix<typename MatrixType::Scalar,
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MatrixType::ColsAtCompileTime, // the number of rows in the "kernel matrix" is the number of cols of the original matrix
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// so that the product "matrix * kernel = zero" makes sense
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Dynamic, // we don't know at compile-time the dimension of the kernel
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MatrixType::Options,
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MatrixType::MaxColsAtCompileTime, // see explanation for 2nd template parameter
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MatrixType::MaxColsAtCompileTime // the kernel is a subspace of the domain space, whose dimension is the number
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// of columns of the original matrix
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> KernelResultType;
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typedef Matrix<typename MatrixType::Scalar,
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MatrixType::RowsAtCompileTime, // the image is a subspace of the destination space, whose dimension is the number
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// of rows of the original matrix
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Dynamic, // we don't know at compile time the dimension of the image (the rank)
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MatrixType::Options,
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MatrixType::MaxRowsAtCompileTime, // the image matrix will consist of columns from the original matrix,
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MatrixType::MaxColsAtCompileTime // so it has the same number of rows and at most as many columns.
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> ImageResultType;
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/**
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* \brief Default Constructor.
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*
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* The default constructor is useful in cases in which the user intends to
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* perform decompositions via LU::compute(const MatrixType&).
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*/
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LU();
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/** Constructor.
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*
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* \param matrix the matrix of which to compute the LU decomposition.
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* It is required to be nonzero.
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*/
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LU(const MatrixType& matrix);
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/** Computes the LU decomposition of the given matrix.
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*
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* \param matrix the matrix of which to compute the LU decomposition.
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* It is required to be nonzero.
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*/
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void compute(const MatrixType& matrix);
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/** \returns the LU decomposition matrix: the upper-triangular part is U, the
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* unit-lower-triangular part is L (at least for square matrices; in the non-square
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* case, special care is needed, see the documentation of class LU).
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*
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* \sa matrixL(), matrixU()
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*/
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inline const MatrixType& matrixLU() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_lu;
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}
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/** \returns a vector of integers, whose size is the number of rows of the matrix being decomposed,
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* representing the P permutation i.e. the permutation of the rows. For its precise meaning,
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* see the examples given in the documentation of class LU.
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*
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* \sa permutationQ()
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*/
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inline const IntColVectorType& permutationP() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_p;
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}
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/** \returns a vector of integers, whose size is the number of columns of the matrix being
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* decomposed, representing the Q permutation i.e. the permutation of the columns.
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* For its precise meaning, see the examples given in the documentation of class LU.
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*
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* \sa permutationP()
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*/
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inline const IntRowVectorType& permutationQ() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_q;
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}
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/** Computes a basis of the kernel of the matrix, also called the null-space of the matrix.
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*
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* \note This method is only allowed on non-invertible matrices, as determined by
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* isInvertible(). Calling it on an invertible matrix will make an assertion fail.
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*
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* \param result a pointer to the matrix in which to store the kernel. The columns of this
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* matrix will be set to form a basis of the kernel (it will be resized
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* if necessary).
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*
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* Example: \include LU_computeKernel.cpp
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* Output: \verbinclude LU_computeKernel.out
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*
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* \sa kernel(), computeImage(), image()
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*/
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template<typename KernelMatrixType>
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void computeKernel(KernelMatrixType *result) const;
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/** Computes a basis of the image of the matrix, also called the column-space or range of he matrix.
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*
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* \note Calling this method on the zero matrix will make an assertion fail.
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*
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* \param result a pointer to the matrix in which to store the image. The columns of this
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* matrix will be set to form a basis of the image (it will be resized
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* if necessary).
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*
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* Example: \include LU_computeImage.cpp
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* Output: \verbinclude LU_computeImage.out
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*
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* \sa image(), computeKernel(), kernel()
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*/
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template<typename ImageMatrixType>
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void computeImage(ImageMatrixType *result) const;
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/** \returns the kernel of the matrix, also called its null-space. The columns of the returned matrix
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* will form a basis of the kernel.
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*
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* \note: this method is only allowed on non-invertible matrices, as determined by
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* isInvertible(). Calling it on an invertible matrix will make an assertion fail.
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*
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* \note: this method returns a matrix by value, which induces some inefficiency.
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* If you prefer to avoid this overhead, use computeKernel() instead.
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*
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* Example: \include LU_kernel.cpp
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* Output: \verbinclude LU_kernel.out
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*
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* \sa computeKernel(), image()
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*/
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const KernelResultType kernel() const;
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/** \returns the image of the matrix, also called its column-space. The columns of the returned matrix
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* will form a basis of the kernel.
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*
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* \note: Calling this method on the zero matrix will make an assertion fail.
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*
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* \note: this method returns a matrix by value, which induces some inefficiency.
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* If you prefer to avoid this overhead, use computeImage() instead.
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*
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* Example: \include LU_image.cpp
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* Output: \verbinclude LU_image.out
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*
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* \sa computeImage(), kernel()
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*/
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const ImageResultType image() const;
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/** This method finds a solution x to the equation Ax=b, where A is the matrix of which
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* *this is the LU decomposition, if any exists.
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*
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* \param b the right-hand-side of the equation to solve. Can be a vector or a matrix,
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* the only requirement in order for the equation to make sense is that
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* b.rows()==A.rows(), where A is the matrix of which *this is the LU decomposition.
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* \param result a pointer to the vector or matrix in which to store the solution, if any exists.
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* Resized if necessary, so that result->rows()==A.cols() and result->cols()==b.cols().
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* If no solution exists, *result is left with undefined coefficients.
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*
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* \returns true if any solution exists, false if no solution exists.
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*
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* \note If there exist more than one solution, this method will arbitrarily choose one.
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* If you need a complete analysis of the space of solutions, take the one solution obtained
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* by this method and add to it elements of the kernel, as determined by kernel().
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*
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* Example: \include LU_solve.cpp
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* Output: \verbinclude LU_solve.out
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*
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* \sa TriangularView::solve(), kernel(), computeKernel(), inverse(), computeInverse()
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*/
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template<typename OtherDerived, typename ResultType>
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bool solve(const MatrixBase<OtherDerived>& b, ResultType *result) const;
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/** \returns the determinant of the matrix of which
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* *this is the LU decomposition. It has only linear complexity
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* (that is, O(n) where n is the dimension of the square matrix)
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* as the LU decomposition has already been computed.
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*
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* \note This is only for square matrices.
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*
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* \note For fixed-size matrices of size up to 4, MatrixBase::determinant() offers
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* optimized paths.
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*
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* \warning a determinant can be very big or small, so for matrices
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* of large enough dimension, there is a risk of overflow/underflow.
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*
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* \sa MatrixBase::determinant()
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*/
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typename ei_traits<MatrixType>::Scalar determinant() const;
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/** \returns the rank of the matrix of which *this is the LU decomposition.
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*
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* \note This is computed at the time of the construction of the LU decomposition. This
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* method does not perform any further computation.
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*/
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inline int rank() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_rank;
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}
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/** \returns the dimension of the kernel of the matrix of which *this is the LU decomposition.
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*
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* \note Since the rank is computed at the time of the construction of the LU decomposition, this
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* method almost does not perform any further computation.
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*/
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inline int dimensionOfKernel() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_lu.cols() - m_rank;
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}
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/** \returns true if the matrix of which *this is the LU decomposition represents an injective
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* linear map, i.e. has trivial kernel; false otherwise.
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*
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* \note Since the rank is computed at the time of the construction of the LU decomposition, this
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* method almost does not perform any further computation.
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*/
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inline bool isInjective() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_rank == m_lu.cols();
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}
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/** \returns true if the matrix of which *this is the LU decomposition represents a surjective
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* linear map; false otherwise.
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*
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* \note Since the rank is computed at the time of the construction of the LU decomposition, this
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* method almost does not perform any further computation.
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*/
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inline bool isSurjective() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return m_rank == m_lu.rows();
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}
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/** \returns true if the matrix of which *this is the LU decomposition is invertible.
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*
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* \note Since the rank is computed at the time of the construction of the LU decomposition, this
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* method almost does not perform any further computation.
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*/
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inline bool isInvertible() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return isInjective() && isSurjective();
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}
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/** Computes the inverse of the matrix of which *this is the LU decomposition.
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*
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* \param result a pointer to the matrix into which to store the inverse. Resized if needed.
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*
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* \note If this matrix is not invertible, *result is left with undefined coefficients.
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* Use isInvertible() to first determine whether this matrix is invertible.
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*
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* \sa MatrixBase::computeInverse(), inverse()
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*/
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inline void computeInverse(MatrixType *result) const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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solve(MatrixType::Identity(m_lu.rows(), m_lu.cols()), result);
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}
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/** \returns the inverse of the matrix of which *this is the LU decomposition.
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*
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* \note If this matrix is not invertible, the returned matrix has undefined coefficients.
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* Use isInvertible() to first determine whether this matrix is invertible.
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*
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* \sa computeInverse(), MatrixBase::inverse()
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*/
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inline MatrixType inverse() const
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{
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MatrixType result;
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computeInverse(&result);
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return result;
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}
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protected:
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const MatrixType* m_originalMatrix;
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MatrixType m_lu;
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IntColVectorType m_p;
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IntRowVectorType m_q;
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int m_det_pq;
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int m_rank;
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RealScalar m_precision;
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};
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template<typename MatrixType>
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LU<MatrixType>::LU()
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: m_originalMatrix(0),
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m_lu(),
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m_p(),
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m_q(),
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m_det_pq(0),
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m_rank(-1),
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m_precision(precision<RealScalar>())
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{
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}
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template<typename MatrixType>
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LU<MatrixType>::LU(const MatrixType& matrix)
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: m_originalMatrix(0),
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m_lu(),
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m_p(),
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m_q(),
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m_det_pq(0),
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m_rank(-1),
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m_precision(precision<RealScalar>())
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{
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compute(matrix);
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}
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template<typename MatrixType>
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void LU<MatrixType>::compute(const MatrixType& matrix)
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{
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m_originalMatrix = &matrix;
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m_lu = matrix;
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m_p.resize(matrix.rows());
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m_q.resize(matrix.cols());
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const int size = matrix.diagonalSize();
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const int rows = matrix.rows();
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const int cols = matrix.cols();
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// this formula comes from experimenting (see "LU precision tuning" thread on the list)
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// and turns out to be identical to Higham's formula used already in LDLt.
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m_precision = machine_epsilon<Scalar>() * size;
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IntColVectorType rows_transpositions(matrix.rows());
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IntRowVectorType cols_transpositions(matrix.cols());
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int number_of_transpositions = 0;
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RealScalar biggest = RealScalar(0);
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m_rank = size;
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for(int k = 0; k < size; ++k)
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{
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int row_of_biggest_in_corner, col_of_biggest_in_corner;
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RealScalar biggest_in_corner;
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biggest_in_corner = m_lu.corner(Eigen::BottomRight, rows-k, cols-k)
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.cwise().abs()
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.maxCoeff(&row_of_biggest_in_corner, &col_of_biggest_in_corner);
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row_of_biggest_in_corner += k;
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col_of_biggest_in_corner += k;
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if(k==0) biggest = biggest_in_corner;
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// if the corner is negligible, then we have less than full rank, and we can finish early
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if(ei_isMuchSmallerThan(biggest_in_corner, biggest, m_precision))
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{
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m_rank = k;
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for(int i = k; i < size; i++)
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{
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rows_transpositions.coeffRef(i) = i;
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cols_transpositions.coeffRef(i) = i;
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}
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break;
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}
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rows_transpositions.coeffRef(k) = row_of_biggest_in_corner;
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cols_transpositions.coeffRef(k) = col_of_biggest_in_corner;
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if(k != row_of_biggest_in_corner) {
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m_lu.row(k).swap(m_lu.row(row_of_biggest_in_corner));
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++number_of_transpositions;
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}
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if(k != col_of_biggest_in_corner) {
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m_lu.col(k).swap(m_lu.col(col_of_biggest_in_corner));
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++number_of_transpositions;
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}
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if(k<rows-1)
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m_lu.col(k).end(rows-k-1) /= m_lu.coeff(k,k);
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if(k<size-1) {
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/* I know it's tempting to replace this for loop by a single matrix product. But actually there's no reason why it
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* should be faster because it's just an exterior vector product; and in practice this gives much slower code with
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* GCC 4.2-4.4 (this is weird, would be interesting to investigate). On the other hand, it would be worth having a variant
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* for row-major matrices, traversing in the other direction for better performance, with a meta selector to compile only
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* one path
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*/
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for(int col = k + 1; col < cols; ++col)
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m_lu.col(col).end(rows-k-1) -= m_lu.col(k).end(rows-k-1) * m_lu.coeff(k,col);
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}
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}
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for(int k = 0; k < matrix.rows(); ++k) m_p.coeffRef(k) = k;
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for(int k = size-1; k >= 0; --k)
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std::swap(m_p.coeffRef(k), m_p.coeffRef(rows_transpositions.coeff(k)));
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for(int k = 0; k < matrix.cols(); ++k) m_q.coeffRef(k) = k;
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for(int k = 0; k < size; ++k)
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std::swap(m_q.coeffRef(k), m_q.coeffRef(cols_transpositions.coeff(k)));
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m_det_pq = (number_of_transpositions%2) ? -1 : 1;
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}
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template<typename MatrixType>
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typename ei_traits<MatrixType>::Scalar LU<MatrixType>::determinant() const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
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return Scalar(m_det_pq) * m_lu.diagonal().prod();
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}
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template<typename MatrixType>
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template<typename KernelMatrixType>
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void LU<MatrixType>::computeKernel(KernelMatrixType *result) const
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{
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ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
|
|
const int dimker = dimensionOfKernel(), cols = m_lu.cols();
|
|
result->resize(cols, dimker);
|
|
|
|
/* Let us use the following lemma:
|
|
*
|
|
* Lemma: If the matrix A has the LU decomposition PAQ = LU,
|
|
* then Ker A = Q(Ker U).
|
|
*
|
|
* Proof: trivial: just keep in mind that P, Q, L are invertible.
|
|
*/
|
|
|
|
/* Thus, all we need to do is to compute Ker U, and then apply Q.
|
|
*
|
|
* U is upper triangular, with eigenvalues sorted so that any zeros appear at the end.
|
|
* Thus, the diagonal of U ends with exactly
|
|
* m_dimKer zero's. Let us use that to construct m_dimKer linearly
|
|
* independent vectors in Ker U.
|
|
*/
|
|
|
|
Matrix<Scalar, Dynamic, Dynamic, MatrixType::Options,
|
|
MatrixType::MaxColsAtCompileTime, MatrixType::MaxColsAtCompileTime>
|
|
y(-m_lu.corner(TopRight, m_rank, dimker));
|
|
|
|
m_lu.corner(TopLeft, m_rank, m_rank)
|
|
.template triangularView<UpperTriangular>().solveInPlace(y);
|
|
|
|
for(int i = 0; i < m_rank; ++i) result->row(m_q.coeff(i)) = y.row(i);
|
|
for(int i = m_rank; i < cols; ++i) result->row(m_q.coeff(i)).setZero();
|
|
for(int k = 0; k < dimker; ++k) result->coeffRef(m_q.coeff(m_rank+k), k) = Scalar(1);
|
|
}
|
|
|
|
template<typename MatrixType>
|
|
const typename LU<MatrixType>::KernelResultType
|
|
LU<MatrixType>::kernel() const
|
|
{
|
|
ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
|
|
KernelResultType result(m_lu.cols(), dimensionOfKernel());
|
|
computeKernel(&result);
|
|
return result;
|
|
}
|
|
|
|
template<typename MatrixType>
|
|
template<typename ImageMatrixType>
|
|
void LU<MatrixType>::computeImage(ImageMatrixType *result) const
|
|
{
|
|
ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
|
|
result->resize(m_originalMatrix->rows(), m_rank);
|
|
for(int i = 0; i < m_rank; ++i)
|
|
result->col(i) = m_originalMatrix->col(m_q.coeff(i));
|
|
}
|
|
|
|
template<typename MatrixType>
|
|
const typename LU<MatrixType>::ImageResultType
|
|
LU<MatrixType>::image() const
|
|
{
|
|
ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
|
|
ImageResultType result(m_originalMatrix->rows(), m_rank);
|
|
computeImage(&result);
|
|
return result;
|
|
}
|
|
|
|
template<typename MatrixType>
|
|
template<typename OtherDerived, typename ResultType>
|
|
bool LU<MatrixType>::solve(
|
|
const MatrixBase<OtherDerived>& b,
|
|
ResultType *result
|
|
) const
|
|
{
|
|
ei_assert(m_originalMatrix != 0 && "LU is not initialized.");
|
|
|
|
/* The decomposition PAQ = LU can be rewritten as A = P^{-1} L U Q^{-1}.
|
|
* So we proceed as follows:
|
|
* Step 1: compute c = Pb.
|
|
* Step 2: replace c by the solution x to Lx = c. Exists because L is invertible.
|
|
* Step 3: replace c by the solution x to Ux = c. Check if a solution really exists.
|
|
* Step 4: result = Qc;
|
|
*/
|
|
|
|
const int rows = m_lu.rows(), cols = m_lu.cols();
|
|
ei_assert(b.rows() == rows);
|
|
const int smalldim = std::min(rows, cols);
|
|
|
|
typename OtherDerived::PlainMatrixType c(b.rows(), b.cols());
|
|
|
|
// Step 1
|
|
for(int i = 0; i < rows; ++i) c.row(m_p.coeff(i)) = b.row(i);
|
|
|
|
// Step 2
|
|
m_lu.corner(Eigen::TopLeft,smalldim,smalldim).template triangularView<UnitLowerTriangular>()
|
|
.solveInPlace(c.corner(Eigen::TopLeft, smalldim, c.cols()));
|
|
if(rows>cols)
|
|
{
|
|
c.corner(Eigen::BottomLeft, rows-cols, c.cols())
|
|
-= m_lu.corner(Eigen::BottomLeft, rows-cols, cols) * c.corner(Eigen::TopLeft, cols, c.cols());
|
|
}
|
|
|
|
// Step 3
|
|
if(!isSurjective())
|
|
{
|
|
// is c is in the image of U ?
|
|
RealScalar biggest_in_c = c.corner(TopLeft, m_rank, c.cols()).cwise().abs().maxCoeff();
|
|
for(int col = 0; col < c.cols(); ++col)
|
|
for(int row = m_rank; row < c.rows(); ++row)
|
|
if(!ei_isMuchSmallerThan(c.coeff(row,col), biggest_in_c, m_precision))
|
|
return false;
|
|
}
|
|
m_lu.corner(TopLeft, m_rank, m_rank)
|
|
.template triangularView<UpperTriangular>()
|
|
.solveInPlace(c.corner(TopLeft, m_rank, c.cols()));
|
|
|
|
// Step 4
|
|
result->resize(m_lu.cols(), b.cols());
|
|
for(int i = 0; i < m_rank; ++i) result->row(m_q.coeff(i)) = c.row(i);
|
|
for(int i = m_rank; i < m_lu.cols(); ++i) result->row(m_q.coeff(i)).setZero();
|
|
return true;
|
|
}
|
|
|
|
/** \lu_module
|
|
*
|
|
* \return the LU decomposition of \c *this.
|
|
*
|
|
* \sa class LU
|
|
*/
|
|
template<typename Derived>
|
|
inline const LU<typename MatrixBase<Derived>::PlainMatrixType>
|
|
MatrixBase<Derived>::lu() const
|
|
{
|
|
return LU<PlainMatrixType>(eval());
|
|
}
|
|
|
|
#endif // EIGEN_LU_H
|