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Added some minor comments.
Adapted some of the doc/snippets.
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@@ -4,5 +4,5 @@ A << 1,2,3, 0,5,6, 0,0,10;
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b << 3, 3, 4;
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cout << "Here is the matrix A:" << endl << A << endl;
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cout << "Here is the vector b:" << endl << b << endl;
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Vector3f x = A.triangularView<UpperTriangular>().solve(b);
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Vector3f x = A.triangularView<Upper>().solve(b);
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cout << "The solution is:" << endl << x << endl;
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@@ -2,5 +2,5 @@ Matrix3f A;
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Vector3f b;
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A << 1,2,3, 0,5,6, 0,0,10;
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b << 3, 3, 4;
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A.triangularView<UpperTriangular>().solveInPlace(b);
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A.triangularView<Upper>().solveInPlace(b);
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cout << "The solution is:" << endl << b << endl;
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@@ -7,10 +7,10 @@ cout << "Here is, up to permutations, its LU decomposition matrix:"
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<< endl << lu.matrixLU() << endl;
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cout << "Here is the L part:" << endl;
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Matrix5x5 l = Matrix5x5::Identity();
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l.block<5,3>(0,0).part<StrictlyLowerTriangular>() = lu.matrixLU();
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l.block<5,3>(0,0).part<StrictlyLower>() = lu.matrixLU();
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cout << l << endl;
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cout << "Here is the U part:" << endl;
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Matrix5x3 u = lu.matrixLU().part<UpperTriangular>();
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Matrix5x3 u = lu.matrixLU().part<Upper>();
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cout << u << endl;
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cout << "Let us now reconstruct the original matrix m:" << endl;
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cout << lu.permutationP().inverse() * l * u * lu.permutationQ().inverse() << endl;
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