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make the dot product linear in the second variable, not the first variable

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Benoit Jacob
2009-08-03 17:20:45 +02:00
parent 912da9fade
commit 523cdedf58
9 changed files with 26 additions and 26 deletions
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8
Eigen/src/Core/Dot.h
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@@ -86,7 +86,7 @@ struct ei_dot_novec_unroller<Derived1, Derived2, Start, 1>
inline static Scalar run(const Derived1& v1, const Derived2& v2)
{
return v1.coeff(Start) * ei_conj(v2.coeff(Start));
return ei_conj(v1.coeff(Start)) * v2.coeff(Start);
}
};
@@ -155,9 +155,9 @@ struct ei_dot_impl<Derived1, Derived2, NoVectorization, NoUnrolling>
{
ei_assert(v1.size()>0 && "you are using a non initialized vector");
Scalar res;
res = v1.coeff(0) * ei_conj(v2.coeff(0));
res = ei_conj(v1.coeff(0)) * v2.coeff(0);
for(int i = 1; i < v1.size(); ++i)
res += v1.coeff(i) * ei_conj(v2.coeff(i));
res += ei_conj(v1.coeff(i)) * v2.coeff(i);
return res;
}
};
@@ -248,7 +248,7 @@ struct ei_dot_impl<Derived1, Derived2, LinearVectorization, CompleteUnrolling>
* \only_for_vectors
*
* \note If the scalar type is complex numbers, then this function returns the hermitian
* (sesquilinear) dot product, linear in the first variable and conjugate-linear in the
* (sesquilinear) dot product, conjugate-linear in the first variable and linear in the
* second variable.
*
* \sa squaredNorm(), norm()